2^x-1>(x+1)/2*(2+(x/2+1)/(log(x/2+1))*(1+1/(log(x/2+1))+2.51/(log^2(x/2+1))))*x^((x/2+1)/(log(x/2+1)) (1+1/(log(x/2+1))+2.51/(log^2(x/2+1))))

Uh oh! Wolfram|Alpha doesn't run without JavaScript.

Please enable JavaScript. If you don't know how, you can find instructionshere.Once you've done that, refresh this page to start using Wolfram|Alpha.